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我感觉有必要擦除流体与固体的试算结果,再进入下一个迭代步。固体好说,只有一个D,我令D=D.oldTime();就能把D的试算结果消去,但流体就很麻烦,因为有很多个变量,我试了半天也不知道该怎么把所有变量的值都擦除掉,恢复迭代前的值
没太看明白