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就是发散了，deltaT太小了，比如1e-15, 1e-16就没有步进

@merlinizlf 在 自动调节时间步长循环计算某一时间步 中说：

一直在循环计算某一个时间

这不是闹鬼了么？时间旅行？一直循环在1-2秒？算完了2秒又回到1秒了？

各位简直就是大佬中的大佬 厉害厉害

ipmitool -I lan -U ADMIN -H 192.168.1.18 sensor thresh FANB lower 100 150 200

Courant Number mean: 0.143461 max: 0.780362
deltaT = 0.000740741
Time = 0.502963

Weighted Re = 9.08136, weighted breakage frequency = 0
MULES limit is done
MULES: Solving for alpha.oil
MULES: Solving for alpha.water
oil fraction, min, max = 0.003 0.000631032 0.00359543
water fraction, min, max = 0.997 0.996405 0.999369
Phase-sum volume fraction, min, max = 1 1 1
DILUPBiCGStab:  Solving for n, Initial residual = 0.000902233, Final residual = 1.49928e-09, No Iterations 1
    Inconsistency value, average, min, max = 2.52405e-11 -0.000617714 0.00282076
    Droplet diameter max, min, mean = 0.0002, 0.0002, 0.0002
MULES limit is done
MULES: Solving for alpha.oil
MULES: Solving for alpha.water
oil fraction, min, max = 0.003 0.000631032 0.00359535
water fraction, min, max = 0.997 0.996405 0.999369
Phase-sum volume fraction, min, max = 1 1 1
DILUPBiCGStab:  Solving for n, Initial residual = 0.000901165, Final residual = 1.49419e-09, No Iterations 1
    Inconsistency value, average, min, max = 2.51988e-11 -0.000617713 0.00282694
    Droplet diameter max, min, mean = 0.0002, 0.0002, 0.0002
Constructing momentum equations
oil min/max T 300 - 300
water min/max T 300 - 300
GAMG:  Solving for p_rgh, Initial residual = 1, Final residual = 0.00559932, No Iterations 6
GAMG:  Solving for p_rgh, Initial residual = 1, Final residual = 0.00565399, No Iterations 6
GAMGPCG:  Solving for p_rgh, Initial residual = 1, Final residual = 3.20997e-08, No Iterations 15
DILUPBiCGStab:  Solving for epsilon.water, Initial residual = 0.000218679, Final residual = 6.3486e-09, No Iterations 2
DILUPBiCGStab:  Solving for k.water, Initial residual = 0.000310738, Final residual = 1.00525e-09, No Iterations 2
ExecutionTime = 91.01 s


Courant Number mean: 0.14345 max: 0.780081
deltaT = 0.000740741
Time = 0.503704

Weighted Re = 9.07954, weighted breakage frequency = 0
MULES limit is done
MULES: Solving for alpha.oil
MULES: Solving for alpha.water
oil fraction, min, max = 0.003 0.000631032 0.00359535
water fraction, min, max = 0.997 0.996405 0.999369
Phase-sum volume fraction, min, max = 1 1 1
DILUPBiCGStab:  Solving for n, Initial residual = 0.000900074, Final residual = 1.47821e-09, No Iterations 1
    Inconsistency value, average, min, max = 2.51619e-11 -0.000617711 0.00283307
    Droplet diameter max, min, mean = 0.0002, 0.0002, 0.0002
MULES limit is done
MULES: Solving for alpha.oil
MULES: Solving for alpha.water
oil fraction, min, max = 0.003 0.000631032 0.00359527
water fraction, min, max = 0.997 0.996405 0.999369
Phase-sum volume fraction, min, max = 1 1 1
DILUPBiCGStab:  Solving for n, Initial residual = 0.000899041, Final residual = 1.47284e-09, No Iterations 1
    Inconsistency value, average, min, max = 2.51262e-11 -0.00061771 0.00283924
    Droplet diameter max, min, mean = 0.0002, 0.0002, 0.0002
Constructing momentum equations
oil min/max T 300 - 300
water min/max T 300 - 300
GAMG:  Solving for p_rgh, Initial residual = 1, Final residual = 0.00559881, No Iterations 6
GAMG:  Solving for p_rgh, Initial residual = 1, Final residual = 0.00565348, No Iterations 6
GAMGPCG:  Solving for p_rgh, Initial residual = 1, Final residual = 3.20563e-08, No Iterations 15
DILUPBiCGStab:  Solving for epsilon.water, Initial residual = 0.000217858, Final residual = 6.31719e-09, No Iterations 2
DILUPBiCGStab:  Solving for k.water, Initial residual = 0.00030924, Final residual = 9.97882e-10, No Iterations 2
ExecutionTime = 91.12 s


Courant Number mean: 0.143439 max: 0.779868
deltaT = 0.000740741
Time = 0.504444

Weighted Re = 9.07807, weighted breakage frequency = 0
MULES limit is done
MULES: Solving for alpha.oil
MULES: Solving for alpha.water
oil fraction, min, max = 0.003 0.000631032 0.00359526
water fraction, min, max = 0.997 0.996405 0.999369
Phase-sum volume fraction, min, max = 1 1 1
DILUPBiCGStab:  Solving for n, Initial residual = 0.000897968, Final residual = 1.45572e-09, No Iterations 1
    Inconsistency value, average, min, max = 2.50956e-11 -0.000617709 0.00284538
    Droplet diameter max, min, mean = 0.0002, 0.0002, 0.0002
MULES limit is done
MULES: Solving for alpha.oil
MULES: Solving for alpha.water
oil fraction, min, max = 0.003 0.000631032 0.00359518
water fraction, min, max = 0.997 0.996405 0.999369
Phase-sum volume fraction, min, max = 1 1 1
DILUPBiCGStab:  Solving for n, Initial residual = 0.000896997, Final residual = 1.44647e-09, No Iterations 1
    Inconsistency value, average, min, max = 2.50645e-11 -0.000617707 0.00285154
    Droplet diameter max, min, mean = 0.0002, 0.0002, 0.0002
Constructing momentum equations
oil min/max T 300 - 300
water min/max T 300 - 300
GAMG:  Solving for p_rgh, Initial residual = 1, Final residual = 0.00559871, No Iterations 6
GAMG:  Solving for p_rgh, Initial residual = 1, Final residual = 0.00565306, No Iterations 6
GAMGPCG:  Solving for p_rgh, Initial residual = 1, Final residual = 3.20133e-08, No Iterations 15
DILUPBiCGStab:  Solving for epsilon.water, Initial residual = 0.000217072, Final residual = 6.28692e-09, No Iterations 2
DILUPBiCGStab:  Solving for k.water, Initial residual = 0.000307752, Final residual = 9.91092e-10, No Iterations 2
ExecutionTime = 91.23 s

各位大佬，这是上面的log文件，我想从中提取几个关键的值：

• Time = 0.000576911里面的0.000576911
• Inconsistency value, average, min, max = -1.34441e-17 -0.000583605 0.000718129里面的0.000718129

目前我使用这个语句：

awk '{if($0~"Inconsist") print}' log

可以提取出来一部分，但是达不到我的需求。我最终想要的是两列数据，类似：

0.000576911  0.000718129

上面是一行的，第一列Time，第二列是后面那个

有没有大佬会搞这个？

@小狗狗 在 关于多块网格并行剖分的负载平衡问题 中说：

没有拓扑连接关系的分块网格呢？

这是什么意思 没太懂

@OItoCFD 在 新写的程序单核计算无问题，但无法并行计算？ 中说：

mpi并行那些需要考虑吗？

一般不需要考虑

除非你的surface场进行一些特殊的插值

@Micro 不，不是那个。我说的主要是alpha方程的子循环。你知道多相流这面alpha方程一般要显性离散，因此要加子循环的。

感谢分享 恭喜你debug成功

@Samuel-Tu 不涉密可以把算例发上来玩玩